Point charges of 4.75 µC and −1.50 µC are placed 0.350 m apart. (Assume the negative charge is located to the right of the positive charge.

Question

Point charges of 4.75 µC and −1.50 µC are placed 0.350 m apart. (Assume the negative charge is located to the right of the positive charge. Include the sign of the value in your answers.)

(a) Where can a third charge be placed so that the net force on it is zero?
_______ m to the right of the −1.50 µC charge
(b) What if both charges are positive?

_______ m to the right of the 1.50 µC charge

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RuslanHeatt 1 year 2021-09-04T22:48:05+00:00 1 Answers 43 views 0

Answers ( )

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    2021-09-04T22:49:14+00:00

    Answer:

    Explanation:

    Let the position of balance point be x distance from 1.5 µC on the right side . Balance point can not be on the left side or between the charges because in that case electric field by both the charges will be in the same direction .

    For equilibrium of field

    k x 4.75 µC / ( .35 +x )² –  k x  1.5  µC / x ² = 0

    4.75 / ( .35 +x )² = 1.5 / x²

    ( .35 +x )² / x² = 4.75 / 1.5

    ( .35 +x )² / x² = 3.167

    ( .35 +x ) / x =  1.78

    .35 + x = 1.78 x

    .78 x = .35

    x = .45 m ( + ve ) to the right of 1.50  µC

    b ) When both the charges are positive , balance point will lie in between them because , electric field will be in opposite direction .

    For equilibrium of field

    k x 4.75 µC / ( .35 – x )² =   k x  1.5  µC / x ²

    4.75 / ( .35 -x )² = 1.5 / x²

    ( .35 -x )² / x² = 4.75 / 1.5

    ( .35 -x )² / x² = 3.167

    ( .35 -x ) / x =  1.78

    .35 -x = 1.78 x

    2.78 x = .35

    x = .126 m  ( – ve ) to the right of 1.50  µC

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