PLEASE HELP ! Someone has offered you a wager on the outcome of a die roll. You will pay him $100 for each time the

Question

PLEASE HELP !

Someone has offered you a wager on the outcome of a die roll. You will pay him
$100 for each time the standard, six-sided die lands on one, and he will pay you $30 for each time the die lands on any other number. Without your awareness, he has loaded the die so that it has a 40% change to land on the number one, and besides
that an equal change to land on any of the values 2 through 6.

What is the expected value of one round of gambling in this scenario?

-$12
-$32
$2
-$22

in progress 0
Thu Nguyệt 3 weeks 2021-08-23T23:30:37+00:00 1 Answers 0 views 0

Answers ( )

    0
    2021-08-23T23:31:58+00:00

    Answer:  Choice D)  -$22

    You’ll lose on average $22 per roll.

    ====================================================

    Explanation:

    Normally there is a 1/6 chance to land on any given side of a standard die, but your friend has loaded the die in a way to make it have a 40% chance to land on “1” and an equal chance to land on anything else. Since there’s a 40% chance to land on “1”, this leaves 100% – 40% = 60% for everything else.  

    Let’s define two events

    • A = event of landing on “1”.
    • B = event of landing on anything else (2 through 6).

    So far we know that P(A) = 0.40 and P(B) = 0.60; I’m using the decimal form of each percentage.

    The net value of event A, which I’ll denote as V(A), is -100 since you pay $100 when event A occurs. So we’ll write V(A) = -100. Also, we know that V(B) = 30 and this value is positive because you receive $30 if event B occurs.

    To recap things so far, we have the following:

    • P(A) = 0.40
    • P(B) = 0.60
    • V(A) = -100
    • V(B) = 30

    Multiply the corresponding probability and net value items together

    • P(A)*V(A) = 0.40*(-100) = -40
    • P(B)*V(B) = 0.60*30 = 18

    Then add up those products:

    -40+18 = -22

    This is the expected value, and it represents the average amount of money you earn for each dice roll. So you’ll lose on average about $22. Because the expected value is not zero, this means this game is not mathematically fair.

    This does not mean that any single die roll you would lose $22; instead it means that if you played the game say 1000 or 10,000 times, then averaging out the wins and losses will get you close to a loss of $22.

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )