PLEASE HELP How many moles of silane gas (SiH4) are present in 8.68 mL measured at 18 0C and 1.50 atm?

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PLEASE HELP
How many moles of silane gas (SiH4) are present in 8.68 mL
measured at 18 0C and 1.50 atm?

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Yến Oanh 5 years 2021-08-18T05:49:39+00:00 1 Answers 39 views 0

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  1. vankhanh
    0
    2021-08-18T05:51:29+00:00
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    Answer: There are 0.00054 moles of silane gas (SiH4) are present in 8.68 mL measured at 18 0C and 1.50 atm.

    Explanation:

    Given: Volume = 8.68 mL (1 mL = 0.001 L) = 8.68 \times 10^{-3} L,    

    Temperature = 18^{o}C = (18 + 273) K = 291 K,

    Pressure = 1.50 atm

    The ideal gas formula is as follows.

    PV = nRT

    where,

    P = pressure

    V = volume

    n = no. of moles

    R = gas constant = 0.0821 L atm/mol K

    T = temperature

    Substitute the values into above formula as follows.

    PV = nRT\\1.50 atm \times 8.68 \times 10^{-3} L = n \times 0.0821 L atm/mol K \times 291 K\\n = \frac{1.50 atm \times 8.68 \times 10^{-3} L}{0.0821 L atm/mol K \times 291 K}\\= \frac{0.01302}{23.8911}\\= 0.00054 mol

    Thus, we can conclude that there are 0.00054 moles of silane gas (SiH4) are present in 8.68 mL measured at 18 0C and 1.50 atm.

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