please help How many grams of barium sulfate are present in 250 of 2.0 M BaS04 solution?

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please help

How many grams of barium sulfate are present in 250 of 2.0 M BaS04 solution?

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MichaelMet 6 months 2021-08-21T06:49:37+00:00 1 Answers 3 views 0

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    2021-08-21T06:51:13+00:00

    Answer:  There are 0.5 grams of barium sulfate are present in 250 of 2.0 M BaSO_{4} solution.

    Explanation:

    Given: Molarity of solution = 2.0 M

    Volume of solution = 250 mL

    Convert mL int L as follows.

    1 mL = 0.001 L\\250 mL = 250 mL \times \frac{0.001 L}{1 mL}\\= 0.25 L

    Molarity is the number of moles of solute present in liter of solution. Hence, molarity of the given BaSO_{4} solution is as follows.

    Molarity = \frac{mass}{Volume (in L)}\\2.0 M = \frac{mass}{0.25 L}\\mass = 0.5 g

    Thus, we can conclude that there are 0.5 grams of barium sulfate are present in 250 of 2.0 M BaSO_{4} solution.

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