Please help!!! A 120 N/m spring is compressed 0.25m and is used to launch a 0.5kg ball. What is the momentum of the ball immediately af

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Please help!!!
A 120 N/m spring is compressed 0.25m and is used to launch a 0.5kg ball. What is the momentum of the ball immediately after it is fired?

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Kim Chi 5 years 2021-08-08T10:22:21+00:00 1 Answers 12 views 0

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  1. kimchi2
    0
    2021-08-08T10:23:42+00:00
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    Answer:

    Momentum of the ball just after the release is 1.94 kg m/s

    Explanation:

    As we know that initially the spring and compressed against the ball

    So here we will have

    \frac{1}{2}mv^2 = \frac{1}{2}kx^2

    now we have

    v = \sqrt{\frac{k}{m}} x

    Here we know that

    mass = 0.5 kg

    k = 120 N/m

    x = 0.25 m

    v = \sqrt{\frac{120}{0.5}}(0.25)

    v = 3.87 m/s

    now we can use formula of momentum here

    P = mv

    P = (0.5)(3.87)

    P = 1.94 kg-m/s

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