phân tích đa thức thành nhân tử a) x^3+y(1-3x^2)+x(3y^2-1)-y^3 b)a^x+a^2y-7x-7y c)x(x+1)^2+x(x-5)-5(x+1)^2

Question

phân tích đa thức thành nhân tử
a) x^3+y(1-3x^2)+x(3y^2-1)-y^3
b)a^x+a^2y-7x-7y
c)x(x+1)^2+x(x-5)-5(x+1)^2

in progress 0
Vodka 1 year 2020-10-13T20:18:23+00:00 2 Answers 164 views 0

Answers ( )

    0
    2020-10-13T20:19:46+00:00

    =))

    `a)`

    `x^3+y(1-3x^2)+x(3y^2-1)-y^3`

    `= (x-y)^3-(x-y)`

    `= (x-y)(x-y+1)(x-y-1)`

    phan-tich-da-thuc-thanh-nhan-tu-a-3-y-1-3-2-3y-2-1-y-3-b-a-a-2y-7-7y-c-1-2-5-5-1-2

    0
    2020-10-13T20:20:18+00:00

    $a)x^3+y.(1-3x^2)+x.(3y^2-1)-y^3_{}$

    $x^3-3x^2y+3xy^2-y^3+y-x_{}$

    $⇔(x-y)^3-(x-y)_{}$

    $b)a^2x+a^2y-7x-7y_{}$

    $⇔x.(a^2-7)+y.(a^2-7)_{}$

    $⇔(a^2-7)(x+y)_{}$

    $c)x.(x+1)^2+x(x-5)-5(x+1)^2_{}$ 

    $⇔(x+1)^2.(x-5)+x.(x-5)_{}$

    $⇔[ (x+1)(x-5)+x].(x-5).(x+1)_{}$

    $⇔(x^2-3x-5)..(x-5)(x+1)_{}$

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )