phân tích đa thức thành nhân tử x ^4+64y^4

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Question

phân tích đa thức thành nhân tử
x ^4+64y^4

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Môn Toán Delwyn 4 years 2020-11-03T21:40:14+00:00 2020-11-03T21:40:14+00:00 2 Answers 138 views 0

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Captcha* Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )

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Farah · Answer 1 · 2020-11-03T21:41:27+00:00

Farah

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2020-11-03T21:41:27+00:00 November 3, 2020 at 9:41 pm

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`x^4+64y^4`

`=x^(4) + 64y^4 + 16x^(2)y^2 – 16x^(2)y^2`

`=(8y^(2) – x^2)^2 + (4xy)^2`

`=(8y^(2) + x^2 – 4xy) (8y^(2) + x^(2) + 4xy) `

`#Study well`

minhkhoi · Answer 2 · 2020-11-03T21:42:07+00:00

minhkhoi

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2020-11-03T21:42:07+00:00 November 3, 2020 at 9:42 pm

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$x^{4}$ $+$ $64$ $y^{4}$

$=$ $x^{4}$ $+$ $64$ $y^{4}$ + $16 x ² y ² - 16 x ² y ²$

$=$ $(8 y ² + x ²) ²$ $-$ $(4 x y) ²$

$=$ $(8 y ² + x ² - 4 x y)$ $(8 y ² + x ² + 4 x y)$