P9. Consider the discussion in Section 1.3 of packet switching versus circuit switching in which an example is provided with a 1 Mbps link.

Question

P9. Consider the discussion in Section 1.3 of packet switching versus circuit switching in which an example is provided with a 1 Mbps link. Users are generating data at a rate of 100 kbps when busy, but are busy generating data only with probability . Suppose that the 1 Mbps link is prop trans t=0 t= trans prop trans t=dtrans prop trans to trans s=2.5⋅108 L=120 bits R=56 kbps. prop trans p=0.1 replaced by a 1 Gbps link. a. What is N, the maximum number of users that can be supported simultaneously under circuit switching?

in progress 0
Ben Gia 5 years 2021-07-19T13:41:51+00:00 1 Answers 99 views 0

Answers ( )

  1. danthu
    0
    2021-07-19T13:43:40+00:00
    Reply

    Answer:

    hello your question is not properly structured  below is the complete question

    . Consider the discussion in Section 1.3 of packet switching versus circuit switching in which an example is provided with a 1 Mbps link. Users are generating data at a rate of 100 kbps when busy, but are busy generating data only with probability . Suppose that the 1 Mbps link is  replaced by a 1 Gbps link. a. What is N, the maximum number of users that can be supported simultaneously under circuit switching?

    answer : N = 1000 users

    Explanation:

    The maximum number of users (n) that can be supported simultaneously under circuit switching

    N =    Total transmission  / rate of data generation by users

    Total transmission  = 1 Gbps = 1 * 10^9 bps

    rate of data generation by user = 100 kbps = 10 * 10^4 bps

    hence the maximum number of users that can be supported simultaneously

    = ( (1* 10^9) / (10 * 10^4) )

    = 10000 users

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )