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On a coordinate plane, triangle A B C is shown. Point A is at (negative 1, 1), point B is at (3, 2), and points C is at (negative 1, negativ
Question
On a coordinate plane, triangle A B C is shown. Point A is at (negative 1, 1), point B is at (3, 2), and points C is at (negative 1, negative 1)
If line segment BC is considered the base of triangle ABC, what is the corresponding height of the triangle?
0.625 units
0.8 units
1.25 units
1.6 units
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Mathematics
3 years
2021-08-24T23:57:45+00:00
2021-08-24T23:57:45+00:00 2 Answers
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Answers ( )
Answer:
D. ( LAST ONE ) 1.6 UNITS
Step-by-step explanation:
IF (x₁,y₁) ,(x₂,y₂) AND (x₃,y₃) ARE THE VERTICES OF THE TRIANGLE.
THEN THE AREA OF THE TRIANGLE IS
HERE x₁= -1,y₁=1 ,x₂=3,y₂=2, and x₃= -1,y₃=-1
THEN THE AREA OF THE TRIANGLE IS
=4 square units
BC is base of the triangle.
Then the length of BC is =
= 5 UNITS
Let the height of the triangle be x.
We know that
The area of triangle is
1/2 x base x height
= (1/2x5xX) square units
According to the problem,
1/2 x 5 x X=4
– X = 4×2/5
X=1.6 UNITS
Therefore the height of the triangle is 1.6 units.
Answer:
D. 1.6
Step-by-step explanation:
magic