On a coordinate plane, a curved line with a minimum value of (negative 1, negative 2), crosses the x-axis at (negative 2, 0) and the y-axis

Question

On a coordinate plane, a curved line with a minimum value of (negative 1, negative 2), crosses the x-axis at (negative 2, 0) and the y-axis at (0, 0). Determine the x-intercepts of the function. Check all that apply. (–2, 0) (–1, –2) (0, 0) (1, 0) (2, 0)On a coordinate plane, a curved line with a minimum value of (negative 1, negative 2), crosses the x-axis at (negative 2, 0) and the y-axis at (0, 0). Determine the x-intercepts of the function. Check all that apply. (–2, 0) (–1, –2) (0, 0) (1, 0) (2, 0)

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Edana Edana 5 years 2021-08-01T04:42:45+00:00 2 Answers 139 views 0

Answers ( )

  1. King
    0
    2021-08-01T04:44:22+00:00
    Reply

    Answer:

    1)  (-2,0)

    2)   (0,0)

    Step-by-step explanation:

    i just took the test. THE FIRST ONE IS WRONG!!!!!

  2. thuthuy
    0
    2021-08-01T04:44:23+00:00
    Reply

    Given:

    A curved line with a minimum value of (-1,-2), crosses the x-axis at (-2, 0) and the y-axis at (0, 0).

    To find:

    x-intercepts of the function.

    Solution:

    The curved line passes through the points (-1,-2), (-2,0) and (0,0).

    We know that, y-coordinate is zero at x-intercepts.

    From the given points, only (-2,0) and (0,0) have 0 as y-coordinate.

    So, x-intercepts of the function are (-2,0) and (0,0).

    Therefore, the correct options are 1 and 3.

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )