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Now assume that the frictional force f is not at its maximum value. What is the relation between the torque Ï„ applied to each wheel by the
Question
Now assume that the frictional force f is not at its maximum value. What is the relation between the torque Ï„ applied to each wheel by the axles and the acceleration a of the car? Once you have the exact expression for the acceleration, make the approximation that the wheels are much lighter than the car as a whole.’
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Physics
5 years
2021-08-06T10:34:16+00:00
2021-08-06T10:34:16+00:00 2 Answers
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Answers ( )
Answer:
The question was dealt with as an incomplete question.
A. The frictional force is in the positive X direction
B. The net force is in the horizontal direction, f is the friction force in each wheel. so the answer is Fnet=4f
C. The weight is distributed equally on each wheel in the Y direction, gives us the formula 4Nwheel-mg=0 with a final answer of N=mg/4
D. torque force at each wheel is tau=rf, linear acceleration is obtained from the sum of the forces 4f=ma, f=tau/r and f=ma/4, (ma/4=tau/r) giving us the final answer of a=4tau/mr (please note that the tau symbol is in the drop down list and looks like a cross between a lowercase r and an upper case T)
Answer:
a)The direction the frictional force will acts is in the positive x direction.
Explanation:
a)The direction the frictional force will acts is in the positive x direction
b)in the horizontal direction, the total force F(total) is equal to 4times the frictional force in the wheel.
F(total)=4f
”f” is taken as the frictional force.
c)4times the normal force on each wheel minus the acceleration equals zero i.e 4N(wheel)-a=0
=4N(wheel)-mg=0
d) torque is the force that tends to bend rotation
ζ=rf
but acceleration=4×frictional force
cross multiply
f=ζ/r
f=ma/4
ma/4=ζ/r
a=4ζ/r