Near San Francisco, where the vertically downward component of the earth’s magnetic field is 4.0 x 10-5 T, a car is traveling forward at 26

Question

Near San Francisco, where the vertically downward component of the earth’s magnetic field is 4.0 x 10-5 T, a car is traveling forward at 26 m/s. The width of the car is 1.9 m. Find the emf induced between the two sides of the car. If positive charge accumulates on the driver’s side, the enter the emf as a positive number. If negative charge accumulates on the driver’s side, the enter the emf as a negative number.

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Thiên Di 3 years 2021-08-22T20:33:11+00:00 2 Answers 17 views 0

Answers ( )

  1. Neala
    0
    2021-08-22T20:34:16+00:00
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    Answer:

    Explanation:

    Magnetic field, B = 4 x 10^-5 T

    velocity, v = 26 m/s

    length, l = 1.9 m

    the formula for the induced emf is given by

    e = B x v x l

    e = 4 x 10^-5 x 26 x 1.9

    e = 1.976 x 10^-3 v

    e = 1.976 mV

  2. kiet
    0
    2021-08-22T20:34:52+00:00
    Reply

    Answer:

    Induced emf will be equal to 1.97\times 10^{-3}volt

    Explanation:

    We have given magnetic field B=4\times 10^{-5}T

    A car is travelling with a speed of 26 m/sec

    So velocity of the car v = 26 m/sec

    Width of the car l = 1.9 m

    We know that emf is equal to

    E=Bvl

    So E=4\times 10^{-5}\times 26\times 1.9=197\times 10^{-5}volt =1.97\times 10^{-3}volt

    So induced emf will be equal to 1.97\times 10^{-3}volt

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