n The graph of which function has a minimum located at (4, -3)? O f(x) = – 5×2 + 4x – 11 f(x) = -2x? + 16x -35 O f(x

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n
The graph of which function has a minimum located at (4, -3)?
O f(x) = – 5×2 + 4x – 11
f(x) = -2x? + 16x -35
O f(x) = 4×2 – 4x + 5
O f(x) = 2×2 – 16x + 35

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Bơ 5 years 2021-07-15T10:55:41+00:00 1 Answers 6 views 0

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  1. sori
    0
    2021-07-15T10:57:37+00:00
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    9514 1404 393

    Answer:

      (d)   f(x) = 2x^2 – 16x + 35

    Step-by-step explanation:

    The x-coordinate of the extreme will be found at …

      x = -b/(2a)

    where the function is f(x) = ax²+bx+c.

    The extreme will be a minimum when a > 0. (eliminates choices A and B)

    The x-coordinates of the extremes are …

      C: -(-4)/(2(4)) = 1/2

      D: -(-16)/(2(2)) = 4 . . . . . matches the requirement

    The appropriate choice is …

      f(x) = 2x^2 – 16x + 35

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )