Multiple-Concept Example 9 reviews the concepts that are important in this problem. A drag racer, starting from rest, speeds up for 391 m wi

Question

Multiple-Concept Example 9 reviews the concepts that are important in this problem. A drag racer, starting from rest, speeds up for 391 m with an acceleration of +18.9 m/s2. A parachute then opens, slowing the car down with an acceleration of -9.92 m/s2. How fast is the racer moving 332 m after the parachute opens?​

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Jezebel 3 years 2021-07-25T13:31:50+00:00 1 Answers 18 views 0

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  1. Neala
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    2021-07-25T13:33:01+00:00
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    Answer:

    V = 90.51 m/s

    Explanation:

    From the given information:

    Initial speed (u) = 0

    Distance (S) = 391 m

    Acceleration (a) = 18.9 m/s²

    Using the relation for the equation of motion:

    v² – u² = 2as

    v² – 0² = 2as

    v² = 2as

    v = \sqrt{2as}

    v = \sqrt{2*18.9*391}

    v = 121.57 m/s

    After the parachute opens:

    The initial velocity = 121.57 m/ss

    Distance S’ = 332 m

    Acceleration = -9.92 m/s²

    How fast is the racer can be determined by using the relation:

    V= \sqrt{v^2 + 2aS'}

    V = \sqrt{121.57^2+ 2 (-9.92)(332)}

    V = 90.51 m/s

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )