mn làm hộ mik vs ak Mik đg cần gấp lắm Cảm ơn mn hiều ak

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mn làm hộ mik vs ak Mik đg cần gấp lắm Cảm ơn mn hiều ak

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mn làm hộ mik vs ak
Mik đg cần gấp lắm
Cảm ơn mn hiều ak
mn-lam-ho-mik-vs-ak-mik-dg-can-gap-lam-cam-on-mn-hieu-ak

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Môn Toán Khoii Minh 4 years 2020-11-24T16:53:03+00:00 2020-11-24T16:53:03+00:00 2 Answers 60 views 0

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Captcha* Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )

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Dau · Answer 1 · 2020-11-24T16:54:22+00:00

Đáp án:

4) $\frac{x + 7}{\sqrt{x} + 3}$

Giải thích các bước giải:

$\begin{array}{l} 1) A = \frac{2 \sqrt{x} (\sqrt{x} - 3) + (\sqrt{x} + 1) (\sqrt{x} + 3) + 11 \sqrt{x} - 3}{(\sqrt{x} + 3) (\sqrt{x} - 3)} \\ = \frac{2 x - 6 \sqrt{x} + x + 4 \sqrt{x} + 3 + 11 \sqrt{x} - 3}{(\sqrt{x} + 3) (\sqrt{x} - 3)} \\ = \frac{3 x + 9 \sqrt{x}}{(\sqrt{x} + 3) (\sqrt{x} - 3)} \\ = \frac{3 \sqrt{x}}{\sqrt{x} - 3} \\ 2) B = \frac{x + 12 + \sqrt{x} - 2 - 4 \sqrt{x} - 8}{(\sqrt{x} + 2) (\sqrt{x} - 2)} \\ = \frac{x - 3 \sqrt{x} + 2}{(\sqrt{x} + 2) (\sqrt{x} - 2)} \\ = \frac{(\sqrt{x} - 1) (\sqrt{x} - 2)}{(\sqrt{x} + 2) (\sqrt{x} - 2)} \\ = \frac{\sqrt{x} - 1}{\sqrt{x} + 2} \\ 3) C = [\frac{x + \sqrt{x} + \sqrt{x}}{(\sqrt{x} - 1) (\sqrt{x} + 1)}] : [\frac{2 \sqrt{x} + 2 - 2 + x}{x (\sqrt{x} + 1)}] \\ = \frac{x + 2 \sqrt{x}}{(\sqrt{x} - 1) (\sqrt{x} + 1)} . \frac{x (\sqrt{x} + 1)}{x + 2 \sqrt{x}} \\ = \frac{x}{\sqrt{x} - 1} \\ 4) D = [\frac{x + \sqrt{x} + 10 - \sqrt{x} - 3}{(\sqrt{x} + 3) (\sqrt{x} - 3)}] . (\sqrt{x} - 3) \\ = \frac{x + 7}{\sqrt{x} + 3} \\ 5) E = \frac{x - 2 - \sqrt{x} - 2 + \sqrt{x}}{\sqrt{x} (\sqrt{x} + 2)} \\ = \frac{x - 4}{\sqrt{x} (\sqrt{x} + 2)} \\ = \frac{(\sqrt{x} + 2) (\sqrt{x} - 2)}{\sqrt{x} (\sqrt{x} + 2)} \\ = \frac{\sqrt{x} - 2}{\sqrt{x}} \\ 6) F = [\frac{\sqrt{x} + 1 + \sqrt{x}}{(\sqrt{x} - 1) (\sqrt{x} + 1)}] : (\frac{\sqrt{x} - \sqrt{x} + 1}{\sqrt{x} - 1}) \\ = \frac{2 \sqrt{x} + 1}{(\sqrt{x} - 1) (\sqrt{x} + 1)} . \frac{\sqrt{x} - 1}{1} \\ = \frac{2 \sqrt{x} + 1}{\sqrt{x} + 1} \\ 7) G = [\frac{x + 3 \sqrt{x} + \sqrt{x} - 5}{(\sqrt{x} + 5) (\sqrt{x} - 5)}] . \frac{\sqrt{x} - 5}{\sqrt{x} + 2} \\ = \frac{x + 4 \sqrt{x} - 5}{(\sqrt{x} + 5) (\sqrt{x} - 5)} . \frac{\sqrt{x} - 5}{\sqrt{x} + 2} \\ = \frac{(\sqrt{x} + 5) (\sqrt{x} - 1)}{(\sqrt{x} + 5) (\sqrt{x} - 5)} . \frac{\sqrt{x} - 5}{\sqrt{x} + 2} \\ = \frac{\sqrt{x} - 1}{\sqrt{x} + 2} \\ 8) H = [\frac{\sqrt{x} + 1 + x}{\sqrt{x} (\sqrt{x} + 1)}] : \frac{\sqrt{x}}{\sqrt{x} (\sqrt{x} + 1)} \\ = \frac{\sqrt{x} + 1 + x}{\sqrt{x} (\sqrt{x} + 1)} . \frac{\sqrt{x} (\sqrt{x} + 1)}{\sqrt{x}} \\ = \frac{x + \sqrt{x} + 1}{\sqrt{x}} \end{array}$

Philomena · Answer 2 · 2020-11-24T16:54:54+00:00

Philomena

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2020-11-24T16:54:54+00:00 November 24, 2020 at 4:54 pm

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