Many home barbeques are fueled with propane gas (C3H8)(C3H8). Part A What mass of carbon dioxide is produced upon the complete combustion of

Question

Many home barbeques are fueled with propane gas (C3H8)(C3H8). Part A What mass of carbon dioxide is produced upon the complete combustion of 27.9 LL of propane (the approximate contents of one 5-gallon tank)

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Ben Gia 6 months 2021-07-11T06:52:58+00:00 1 Answers 89 views 0

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    2021-07-11T06:54:56+00:00

    Answer:

    41264 g of CO₂

    Explanation:

    Combustion reaction is:

    C₃H₈ + 5O₂ →  3CO₂  +  4H₂O

    1 mol of propane react to 5 moles of oxygen in order to proudce 3 moles of carbon dioxide and 4 moles of water.

    In a combustion reaction, our reactant reacts to oxygen and the products are always CO₂ and water.

    We have the volume of propane but we need moles of it, so we need to apply density.

    Density = mass / volume so mass = density . volume.

    Density of propane is: 493 g/L

    Mass of propane is 493 g/L . 27.9L = 13754.7 g

    We convert mass to moles: 13754.7 g . 1 mol/ 44g = 312.6 moles

    According to reaction, 1 mol of propane can produce 3 moles of CO₂

    Our 312.6 moles will produce 312.6 . 3 = 937.8 moles

    We convert moles to mass: 937.8 mol . 44 g/mol = 41264 g

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