Light from a helium-neon laser (λ = 633 nm) is used to illuminate two narrow slits. The interference pattern is observed on a screen 2.5 m

Question

Light from a helium-neon laser (λ = 633 nm) is used to illuminate two narrow slits. The interference pattern is observed on a screen 2.5 m behind the slits. Eleven bright fringes are seen, spanning a distance of 54 mm. What is the spacing (in mm) between the slits?

in progress 0
Verity 3 years 2021-08-05T20:02:02+00:00 1 Answers 12 views 0

Answers ( )

  1. Jezebel
    0
    2021-08-05T20:03:49+00:00
    Reply

    Answer:

    The  value is  d = 0.000293 \ m

    Explanation:

    From the question we are told that

       The wavelength is  \lambda = 633 \ nm = 633 *10^{-9} \ m

        The  distance of the screen is  D = 2.5 \ m

        The  order of the bright fringes is  n = 10 (10  fringe + central maximum = eleven bright fringes )

          The distance between the fringe is  y = 54 \ mm = 0.054 \ m

    Generally the condition for constructive interference is  

            d sin \theta = n * \lambda

    =>     d = \frac{n * \lambda}{sin \theta}

    Now  from the SOHCAHTOA rule the angle  sin \theta is mathematically represented as

          sin (\theta) = \frac{y}{D}

    So  

              d = \frac{n * \lambda}{\frac{y}{D} }

    =>       d = \frac{10 * 633 *10^{-9}}{\frac{0.054}{ 2.5} }

    =>      d = 0.000293 \ m

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )