let h(x)=6-2/3x. a. find h(-6). b. Find the value of x so that h(x)=2

Question

let h(x)=6-2/3x.
a. find h(-6).
b. Find the value of x so that h(x)=2

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Delwyn 5 years 2021-08-31T20:50:01+00:00 1 Answers 20 views 0

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  1. Bo
    0
    2021-08-31T20:51:03+00:00
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    Answer:

    a. h(-6)=10

    b. x=6

    Step-by-step explanation:

    a.

    To find h(-6), you want to plug in x=-6 into h(x).

    h(-6)=6-\frac{2}{3}(-6)          [multiply]

    h(-6)=6+4                  [add]

    h(-6)=10

    Now, we know that h(-6)=10.

    ——————————————————————————————————

    b.

    To find the value of x, we want to set h(x) equal to 2.

    2=6-\frac{2}{3} x                        [subtract both sides by 6]

    -4=-\frac{2}{3}x                         [multiply both sides by -3/2]

    x=6

    Now, we know that x=6.

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )