Jen recently rode her bicycle to visit her friend who lives 6 miles away. On her way there, her average speed was & miles per hou

Question

Jen recently rode her bicycle to visit her friend who lives 6 miles away. On her way there, her average speed was & miles per hour faster than on her way home. If jen
spent a total of 2 hours bicycling find the two rates.

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Adela 3 years 2021-08-01T18:21:36+00:00 1 Answers 62 views 0

Answers ( )

  1. RuslanHeatt
    0
    2021-08-01T18:23:23+00:00
    Reply

    Answer:

    Let +s+ = her average speed going back home

    +s+%2B+5+ = her average speed going to friend’s house

    Let +t+ = her time in hrs going back home

    +2+-+t+ = her time in hrs going to friend’s house

    —————————————————

    Equation for going to friend’s house:

    (1) +12+=+%28+s+%2B+5+%29%2A%28+2+-+t+%29+

    Equation for going back home:

    (2) +12+=+s%2At+

    ——————————–

    (2) +t+=+12%2Fs+

    Plug this result back into (1)

    (1) +12+=+%28+s+%2B+5+%29%2A%28+2+-+12%2Fs+%29+

    (1) +12+=+2s+%2B+10+-+12+-+60%2Fs+

    (1) +14+=+2s+-+60%2Fs+

    (1) +14s+=+2s%5E2+-+60+

    (1) +2s%5E2+-+14s+-+60+=+0+

    (1) +s%5E2+-+7s+-+30+=+0+

    (1) +%28+s+-+10+%29%2A%28+s+%2B+3+%29+=+0+ ( by looking at it )

    (1) +s+=+10+ ( can’t use the negative solution )

    and

    +s+%2B+5+=+15+

    Going to friend’s house: 15 mi/hr

    Going back home: 10 mi/hr

    ———————————–

    check:

    (2) +12+=+s%2At+

    (2) +12+=+10t+

    (2) +t+=+1.2+ hrs

    and

    (1) +12+=+%28+s+%2B+5+%29%2A%28+2+-+t+%29+

    (1) +12+=+15%2A%28+2+-+t+%29+

    (1) +12+=+30+-+15t+

    (1) +15t+=+30+-+12+

    (1) +15t+=+18+

    (1) +t+=+1.2+ hrs

    Step-by-step explanation:

    hope it help brainliest pls

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