In ΔWXY, w = 410 inches, x = 530 inches and y=830 inches. Find the area of ΔWXY to the nearest 10th of an square inch.

Question

In ΔWXY, w = 410 inches, x = 530 inches and y=830 inches. Find the area of ΔWXY to the nearest 10th of an square inch.

in progress 0
Ngọc Khuê 5 years 2021-08-26T02:49:48+00:00 1 Answers 45 views 0

Answers ( )

  1. thanhha
    0
    2021-08-26T02:51:21+00:00
    Reply

    Answer:

    90,597 square inches

    Step-by-step explanation:

    In ΔWXY, w = 410 inches, x = 530 inches and y=830 inches. Find the area of ΔWXY to the nearest 10th of an square inch.

    We solve using Heron’s formula

    A = √s(s -a)(s – b) (s – c)

    s = a + b + c/2

    a = 410 inches

    b = 530 inches

    c = 830 inches

    Hence,

    s = 410 + 530 + 830/2

    s = 885

    A = √885(885 – 410)(885 – 530)(885 – 830)

    A = 90,597.030166557 square inches

    Approximately = 90,597.0 square inches

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )