in what ratio of line x-y-2=0 divides the line segment joining (3,-1)and (8,9)​

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in what ratio of line x-y-2=0 divides the line segment joining (3,-1)and (8,9)​

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Delwyn 3 years 2021-08-16T21:46:28+00:00 1 Answers 11 views 0

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  1. hongcuc2
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    2021-08-16T21:48:09+00:00
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    Answer:

    The ratio in which the line x-y-2=0 divides the line joining A(3,-1) and B(8,9) is in the ratio 2:3

    Step-by-step explanation:

    Let (x, y) be the coordinates of point of intersection.

    Hence x=(a*8+1*3)(a+1) = (8a+3)/(a+1)

    and

    y = {a*9+1*(-1)}/(a+1)=(9a-1)/(a+1)

    Since this point lies on the line x-y-2=0

    Hence (8a+3)/(a+1)-(9a-1)/(a+1)-2=0

    i.e. 8a+3–9a+1–2(a+1)=0

    Or 8a+3–9a+1–2a-2=0

    i.e.-3a+2=0

    Hence a=2/3

    hence the ratio in which the line x-y-2=0 divides the line joining A(3,-1) and B(8,9) in the ratio 2/3:1

    i.e. 2:3

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )