In ΔTUV, the measure of ∠V=90°, the measure of ∠T=52°, and UV = 7 feet. Find the length of VT to the nearest tenth of a foot.

In ΔTUV, the measure of ∠V=90°, the measure of ∠T=52°, and UV = 7 feet. Find the length of VT to the nearest tenth of a foot.

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  1. Answer:

    5.5 feet

    Step-by-step explanation:

    We have VT adjacent to angle T.

    We know that VU, side length that is opposite to T, is 7.

    We use the TAN function, which is opposite/adjacent, on T 🙂

    tan(52) = 7/x

    x tan(52) = 7

    x = 7/tan(52) =~ that’s around 5.469 –> 5.5 feet

    YAS

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