In the year 1178, five monks at Canterbury Cathedral in England observed what appeared to be an asteroid colliding with the moon, causing a

Question

In the year 1178, five monks at Canterbury Cathedral in England observed what appeared to be an asteroid colliding with the moon, causing a red glow in and around it. It is hypothesized that this event created the crater Giordano Bruno, which is right on the edge of the area we can usually see from Earth.

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Lệ Thu 5 years 2021-07-18T22:06:25+00:00 2 Answers 48 views 0

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    2021-07-18T22:08:09+00:00

    Answer:

    Incomplete question: The question is: How logn after the asteroid hit the Moon, which is 3.84×10⁵km away, would the light first arrive on Earth in seconds?

    The answer is 1.28 s

    Explanation:

    Data given:

    d = distance = 3.84×10⁵km = 3.84×10⁸m

    v = velocity of light = 3×10⁸ m/s

    The time will be:

    t=\frac{d}{v} =\frac{3.84x10^{8} }{3x10^{8} } =1.28s

    0
    2021-07-18T22:08:18+00:00

    Complete Question

    In the year 1178, five monks at Canterbury Cathedral in England observed what appeared to be an asteroid colliding with the moon, causing a red glow in and around it. It is hypothesized that this event created the crater Giordano Bruno, which is right on the edge of the area we can usually see from Earth.

    How long after the asteroid hit the Moon,which is 3.84 *10^5 km away ,would the light first arrive on the earth in seconds

    Answer:

    The time it would take is  t = 1.28 \ sec

    Explanation:

    The objective of this question is to obtain the time the light would arrive earth

          We are told that the distance from moon to  earth is  

                      D = 3.84*10^5km = 3.84*10^5 * 1000 = 3.84*10^8m

    Now generally time is mathematically represented as

                              t = \frac{D}{c}

    The c here is the speed of light which has a value of c = 3*10^8 m/s

            Now substituting values

                            t = \frac{3.84 * 10^8 }{3*10^8}

                               = 1.28 \ sec

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