In outer space a five KG object moving in to the right at 4M/S and a two KG object moving to the left at 3MS collide and stick together thei

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In outer space a five KG object moving in to the right at 4M/S and a two KG object moving to the left at 3MS collide and stick together their speed after the collision is

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Khang Minh 5 years 2021-08-16T00:26:00+00:00 1 Answers 15 views 0

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  1. ngochoa
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    2021-08-16T00:27:18+00:00
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    Answer:

    Combined speed, V = 2 m/s

    Explanation:

    Given that,

    Mass of object 1, m = 5 kg

    Speed of object 1, u = 4 m/s (due right)

    Mass of object 2, m’ = 2 kg

    Speed of object 2, u’ = -3 m/s (due left)

    Let V is the speed of the objects after the collision. Here, both objects stick to each other. Therefore, the momentum remains conserved. So,

    mu+m'u'=(m+m')V\\\\V=\dfrac{mu+m'u'}{(m+m')}\\\\V=\dfrac{5\times 4+2\times (-3)}{(5+2)}\\\\V=2\ m/s

    So, the combined speed of the masses will be 2 m/s.

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )