In certain ranges of a piano keyboard, more than one string is tuned to the same note to provide extra loudness. For example, the note at 11

Question

In certain ranges of a piano keyboard, more than one string is tuned to the same note to provide extra loudness. For example, the note at 110 Hz has two strings at this frequency. If one string slips from its normal tension of 596 N to 538.00 N, what beat frequency is heard when the hammer strikes the two strings simultaneously

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Vân Khánh 3 years 2021-08-27T07:54:46+00:00 1 Answers 11 views 0

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    2021-08-27T07:56:45+00:00

    Answer:

    5.4893 beats/sec

    Explanation:

    We have f_1 and f_2 as frequency of two waves

    also we know that according to question

    f_2=f_1\sqrt{\frac{F'}{F} }

    F and F’ are forces on the two frequencies.

    therefore, beat frequency is

    f=f_1-f_2=f_1-f_1\sqrt{\frac{F'}{F} }\\=110(1-\sqrt{\frac{538}{596} })\\=5.4893 \text{ beats/sec}

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