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## In an emergency an airplane needs to land on a short runway at Albany County Airport. The plane comes in for a landing with a speed of 95 m/

Question

In an emergency an airplane needs to land on a short runway at Albany County Airport. The plane comes in for a landing with a speed of 95 m/s. The planes maximum magnitude of acceleration is 7.07 m/s2 as it comes to a stop. (a) What is the minimum time interval needed for this plane to stop?

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Physics
2 months
2021-07-22T13:07:41+00:00
2021-07-22T13:07:41+00:00 1 Answers
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## Answers ( )

Answer:t = 13.43 s

Explanation:In order to find the minimum time required by the plane to stop, we will use the first equation of motion. The first equation of motion is written as follows:

Vf = Vi + atwhere,

Vf = Final Velocity of the Plane = 0 m/s (Since, the plane finally stops)

Vi = Initial Velocity of the Plane = 95 m/s

a = deceleration of the plane = – 7.07 m/s²

t = minimum time interval needed to stop the plane = ?

Therefore,

0 m/s = 95 m/s + (- 7.07 m/s²)tt = (95 m/s)/(7.07 m/s²)t = 13.43 s