In a certain region of space, a uniform electric field is in the x direction. A particle with negative charge is carried from x 5 20.0 cm to

Question

In a certain region of space, a uniform electric field is in the x direction. A particle with negative charge is carried from x 5 20.0 cm to x 5 60.0 cm. (i) Does the electric po- tential energy of the charge-field system (a) increase, (b) re- main constant, (c) decrease, or (d) change unpredictably

in progress 0
Thái Dương 3 years 2021-09-04T09:42:47+00:00 1 Answers 29 views 0

Answers ( )

  1. binhan
    0
    2021-09-04T09:43:52+00:00
    Reply

    Answer:

    (a) increase

    Explanation:

    On a line graph; we have the x-axis to the positive side and the negative side .In a positive x-axis direction, the force is usually positive, vice versa the negative side as well.

    The change in the potential energy of a charge field-system can be given as:

    \delta U= -q(EdsCos \theta)

    where;

    q = positive test charge

    E = Electric field

    ds = displacement between thee charge positions

    θ  = Angle between the electric field and the displacement.

    Given that:

    Charge of the particle = -q

    displacement = (60.0 -20.0)cm = 40.0 cm

    θ = 0

    Replacing our values in the above equation, we have:

    \delta U = -(-q)(60Cos 0)

    \delta U = qEds

    Since the potential energy of the system is positive, therefor the electric potential energy also increases.

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )