If you were to drop a rock from a tall building, assuming that it had not yet hit the ground, and neglecting air resistance, after 10 s: How

Question

If you were to drop a rock from a tall building, assuming that it had not yet hit the ground, and neglecting air resistance, after 10 s: How fast (speed) would it be traveling (in m/s)

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Khoii Minh 4 years 2021-08-01T04:43:07+00:00 1 Answers 12 views 0

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    2021-08-01T04:44:18+00:00

    Answer:

    Explanation:

    Using the equation of motion v = u + at to get the speed at which the object would be travelling.

    v is the final speed (in m/s)

    u is the initial velocity (in m/s)

    a is the acceleration (in m/s²)

    t is the time taken (in  secs)

    Given parameters

    u = 0m/s

    t = 10s

    a = g = 9.8m/s²

    Substituting this values into the formula;

    v = 0+9.8(10)

    v = 0+ 98

    v  = 98m/s

    Hence the rock will be travelling at a speed of 98m/s.

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