If you react 156.0 g of calcium chloride with an excess NaOH, how much sodium chloride should you get?

Question

If you react 156.0 g of calcium chloride with an excess NaOH, how much sodium chloride should you get?

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Orla Orla 2 months 2021-07-31T19:09:23+00:00 1 Answers 2 views 0

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    2021-07-31T19:11:14+00:00

    Answer:

    164.3g of NaCl

    Explanation:

    Based on the chemical equation:

    CaCl2 + 2NaOH → 2NaCl + Ca(OH)2

    where 1 mole of CaCl2 reacts with 2 moles of NaOH

    To solve this question we must convert the mass of CaCl2 to moles. Using the chemical equation we can find the moles of NaCl and its mass:

    Moles CaCl2 -Molar mass: 110.98g/mol-

    156.0g CaCl₂ * (1mol / 110.98g) = 1.4057 moles CaCl2

    Moles NaCl:

    1.4057 moles CaCl2 * (2mol NaCl / 1mol CaCl2) = 2.811 moles NaCl

    Mass NaCl -Molar mass: 58.44g/mol-

    2.811 moles NaCl * (58.44g / mol) = 164.3g of NaCl

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )