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If the specific heat of iron = 0.46J C, how much heat is needed to warm 50 g of iron from 20C to 100C
Question
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Answers ( )
Answer:
1840 J
Explanation:
From the question given above, the following data were obtained:
Specific heat capacity (C) = 0.46 J/gºC
Mass (M) = 50 g
Initial temperature (T₁) = 20 °C
Final temperature (T₂) = 100 °C
Heat (Q) required =?
Next, we shall determine the change in the temperature. This can be obtained as follow:
Initial temperature (T₁) = 20 °C
Final temperature (T₂) = 100 °C
Change in temperature (ΔT) =?
ΔT = T₂ – T₁
ΔT = 100 – 20
ΔT = 80 °C
Finally, we shall determine the heat required. This can be obtained as follow:
Specific heat capacity (C) = 0.46 J/gºC
Mass (M) = 50 g
Change in temperature (ΔT) = 80 °C
Heat (Q) required =?
Q = MCΔT
Q = 50 × 0.46 × 80
Q = 1840 J
Thus, 1840 J of heat energy is required.