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## If the specific heat of iron = 0.46J C, how much heat is needed to warm 50 g of iron from 20C to 100C

Question

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## Answers ( )

Answer:

1840 J

Explanation:

From the question given above, the following data were obtained:

Specific heat capacity (C) = 0.46 J/gºC

Mass (M) = 50 g

Initial temperature (T₁) = 20 °C

Final temperature (T₂) = 100 °C

Heat (Q) required =?

Next, we shall determine the change in the temperature. This can be obtained as follow:

Initial temperature (T₁) = 20 °C

Final temperature (T₂) = 100 °C

Change in temperature (ΔT) =?

ΔT = T₂ – T₁

ΔT = 100 – 20

ΔT = 80 °C

Finally, we shall determine the heat required. This can be obtained as follow:

Specific heat capacity (C) = 0.46 J/gºC

Mass (M) = 50 g

Change in temperature (ΔT) = 80 °C

Heat (Q) required =?

Q = MCΔT

Q = 50 × 0.46 × 80

Q = 1840 J

Thus, 1840 J of heat energy is required.