If the mass defect for a radionuclide is –8.7839×10-30 kg, what’s the binding energy per atom? Question 7 options: A)

Home/ English/Chemistry/If the mass defect for a radionuclide is –8.7839×10-30 kg, what’s the binding energy per atom? Question 7 options: A)

Question

If the mass defect for a radionuclide is –8.7839×10-30 kg, what’s the binding energy per atom? Question 7 options: A)

Question

If the mass defect for a radionuclide is –8.7839×10-30 kg, what’s the binding energy per atom?
Question 7 options:

A)

–7.8944×10-13 J/atom

B)

–4.76×1011 J/atom

C)

–7.8944×10-13 kJ/atom

D)

7.8944×10-13 J/atom

in progress 0

Chemistry Nguyệt Ánh 3 years 2021-08-26T05:46:32+00:00 2021-08-26T05:46:32+00:00 1 Answers 19 views 0

Name*

E-Mail*

Website

Featured image

Browse

Captcha* Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )

Answer*

Dulcie · Answer 1 · 2021-08-26T05:47:52+00:00

Dulcie

0

2021-08-26T05:47:52+00:00 August 26, 2021 at 5:47 am

Reply

Answer:

A) –7.8944×10-13 J/atom

Explanation:

Mass defect of a radionuclide (m)

$=-8.7839$ × $10^{-30} kg$

Formula for binding energy

$E=mc^{2}$

$=(-8.7839x10^{-30} kg)(3x10^{8} m/s)^{2}$

$E=-7.8944x10^{-13} J/atom$