If the mass defect for a radionuclide is –8.7839×10-30 kg, what’s the binding energy per atom? Question 7 options: A)

Question

If the mass defect for a radionuclide is –8.7839×10-30 kg, what’s the binding energy per atom?
Question 7 options:

A)

–7.8944×10-13 J/atom

B)

–4.76×1011 J/atom

C)

–7.8944×10-13 kJ/atom

D)

7.8944×10-13 J/atom

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Nguyệt Ánh 5 months 2021-08-26T05:46:32+00:00 1 Answers 2 views 0

Answers ( )

    0
    2021-08-26T05:47:52+00:00

    Answer:

    A) –7.8944×10-13 J/atom

    Explanation:

    Mass defect of a radionuclide (m)

    =-8.7839×10^{-30} kg

    Formula for binding energy

    E=mc^{2}

       =(-8.7839x10^{-30} kg)(3x10^{8} m/s)^{2}

    E=-7.8944x10^{-13} J/atom

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