If a projectile is fired with an initial velocity of V meters per second at an angle A above the horizontal and air resistance is assumed to

Question

If a projectile is fired with an initial velocity of V meters per second at an angle A above the horizontal and air resistance is assumed to be negligible, then its position after t seconds is given by the parametric equations

x=(Vcos(A))t,
y=(Vsin(A))t−12gt2,

A gun is fired with a = 30° and v0 = 500 m/s. When will the bullet hit the ground?

in progress 0
Neala 3 years 2021-07-22T13:16:47+00:00 1 Answers 40 views 0

Answers ( )

  1. Helga
    0
    2021-07-22T13:18:01+00:00
    Reply

    Answer:

    The projectile will hit the ground after about 1min 41 seconds

    T=100.7 seconds

    Explanation:

    The time of flight for a projectile motion is expressed as

    T=(2usin0)/g

    Where u is the initial velocity

    Theta 0 is the projected angle

    Assuming g=9.81m/s

    Given data

    Theta 0= 30°

    u =500m/s

    Substituting our data into the expression we have

    T=(2*500*sin30°)/9.81

    T=(1000*−0.988)/9.81

    T=988/9.81

    T=100.7 second

    The projectile will hit the ground after about 1min 41 seconds

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )