If a heat engine takes in 4565 kJ and gives up 2955 kJ during one cycle, what is the engine’s efficiency?

Question

If a heat engine takes in 4565 kJ and gives up 2955 kJ during one cycle, what is the engine’s efficiency?

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RuslanHeatt 4 years 2021-07-18T22:19:59+00:00 1 Answers 6 views 0

Answers ( )

  1. thugiang
    0
    2021-07-18T22:21:29+00:00
    Reply

    The engine efficiency is 64.73 %

    Explanation:

    Given data

    To find the engine’s efficiency we have the formula,

    Energy input- 4565 KJ

    Energy output – 2955KJ

    Efficiency= energy output/ energy input ×100%

     =2955/4565

      =0.6473 ×100

    η               =64.73 %

    The engine efficiency is 64.73 %

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