If ( 4x – 2 ) ( x + 9 ) – 3x = ax2 + bx + c, what is the value of b. The 2 is and exponent please help me 

Question

If ( 4x – 2 ) ( x + 9 ) – 3x = ax2 + bx + c, what is the value of b. The 2 is and exponent please help me 

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RuslanHeatt 5 years 2021-08-20T19:15:54+00:00 2 Answers 7 views 0

Answers ( )

  1. King
    0
    2021-08-20T19:16:55+00:00
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    Answer:

    b = -34

    Step-by-step explanation:

    Use ” ^ ” to indicate exponentiation:  

    ( 4x – 2 ) ( x + 9 ) – 3x = ax^2 + bx + c

    Perform the indicated multiplication:

    4x^2 + 36x – 2x – 18 – 3x becomes

    4x^2 – 34x – 18                so b = -34

  2. thuthuy
    0
    2021-08-20T19:17:28+00:00
    Reply

    Answer:

    b=31 in ax^2+bx+c

    Step-by-step explanation:

    Hi there!

    ( 4x - 2 ) ( x + 9 ) - 3x

    Our goal is to expand this equation and put it in the form ax^2+bx+c. Firstly, multiply the first two binomials (in the parentheses):

    = 4x(x+9)-2(x+9)-3x\\= 4x^2+36x-2(x+9)-3x\\= 4x^2+36x-2x-18-3x

    Now, we can combine like terms (terms with like variables):

    = 4x^2+36x-2x-3x-18\\= 4x^2+31x-18

    Now, in this equation, we can easily identify that 31 is the value of b in ax^2+bx+c.

    I hope this helps!

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )