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## Identify the calculations possible using only 28.02 g/mol as a conversion factor. Select one or more:

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The question is incomplete, the complete question is:Identify the calculations possible using only 28.02 g/mol as a conversion factor. Select one or more:

(a): Calculate the grams of in 10.58 L of nitrogen gas

(b): Calculate the grams of in moles of nitrogen gas

(c): Calculate the moles of molecules in 3.94 grams of nitrogen gas

(d): Calculate the moles of molecules in 4.73 L of nitrogen gas

Answer:The correct options are (b) and (c).Explanation:We are given:Molar mass of = 28.02 g/mol

The number of moles is defined as the ratio of the mass of a substance to its molar mass.

The equation used is:At STP conditions:1 mole of gas occupies 22.4 L of volume

For the given options:Volume is given and to calculate the mass of , we need to use both the conversion factors above.(a):The equation formed will be:Mass of =

Moles are given and to calculate the mass of , we need only the first conversion factor.(b):The equation formed will be:Mass of =

Mass is given and to calculate the moles of molecules, we need only the first conversion factor.(c):The equation formed will be:Moles of molecules =

Volume is given and to calculate the moles of molecules, we need only the second conversion factor.(d):The equation formed will be:Moles of molecules =

Hence, the correct option is (b) and (c)