I had to hire a plumber to come fix a leaky pipe. The first day he worked 3 hours and charged me $450. The next day he came back and finishe

Question

I had to hire a plumber to come fix a leaky pipe. The first day he worked 3 hours and charged me $450. The next day he came back and finished the job working another 5 hours charging me $700. Find the equation that represents the cost, y, after x hours of working.​

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Diễm Kiều 4 years 2021-07-27T10:15:53+00:00 1 Answers 8 views 0

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    2021-07-27T10:17:36+00:00

    Answer:

    143.75X = Y

    Explanation:

    Since I had to hire a plumber to come fix a leaky pipe, and the first day he worked 3 hours and charged me $ 450, while the next day he came back and finished the job working another 5 hours charging me $ 700, to find the equation that represents the cost, and, after x hours of working, the following calculation must be performed:

    (450 + 700) / (3 + 5) = Y

    1150/8 = Y

    143.75 = Y

    Thus, the hourly cost of the plumber’s work was $ 143.75.

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