Hydrochloric acid is widely used as a laboratory reagent in refining ore for the production of tin and tantalum, and as a catalyst in organi

Question

Hydrochloric acid is widely used as a laboratory reagent in refining ore for the production of tin and tantalum, and as a catalyst in organic reactions. Calculate the number of moles of HCl in 62.85 mL of 0.453 M hydrochloric acid.

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Orla Orla 4 years 2021-07-13T11:09:57+00:00 1 Answers 166 views 0

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  1. thienhuong
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    2021-07-13T11:11:30+00:00
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    Answer: 0.0285 moles of HCl is present in given amount of solution.

    Explanation:

    Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L. The formula used to calculate molarity:

    \text{Molarity of solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (mL)}} …..(1)

    Given values:

    Molarity of HCl = 0.453 M

    Volume of solution = 62.85 mL

    Putting values in equation 1, we get:

    0.453mol/L=\frac{\text{Moles of HCl}\times 1000}{62.85}\\\\\text{Moles of HCl}=\frac{0.453\times 62.85}{1000}=0.0285moles

    Hence, 0.0285 moles of HCl is present in given amount of solution.

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