Hurry. Answer quick! Question 1) A 2kg ball travelling horizontally at 2 m s – ¹ rebounds horizontally off a wall at the same spe

Question

Hurry. Answer quick!
Question 1) A 2kg ball travelling horizontally at 2 m s – ¹ rebounds horizontally off a wall at the same speed, what is the change in momentum? Question 2) Two 5kg bodies approach each other, both having speed of 2 ms-¹. What is the total momentum?
Please answer quick!

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Tryphena 5 years 2021-07-26T02:30:41+00:00 1 Answers 31 views 0

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  1. MichaelMet
    0
    2021-07-26T02:32:35+00:00
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    Answer:

    1) The change in momentum of the ball is 8 kgm/s

    2) The total momentum of the bodies is 20 kgm/s

    Explanation:

    1)

    Given;

    mass of the ball, m = 2 kg

    initial velocity of the ball, v₁ = 2 m/s

    final velocity of the ball, v₂ = -2 m/s (the ball rebounds)

    The change in momentum of the ball is given by;

    ΔP = Δmv

    ΔP = mv₁ – mv₂

    ΔP = m(v₁ – v₂)

    ΔP = 2(2 – (-2))

    ΔP = 2(2 + 2)

    ΔP = 8 kgm/s

    2)

    Given;

    mass of the first body, m₁ = 5kg

    mass of the second body, m₂ = 5kg

    speed of the first body, v₁ = 2 m/s

    speed of the second body, v₂ = 2 m/s

    The total momentum of the bodies is given by

    P = m₁v₁ + m₂v₂

    P = (5 x 2) + (5 x 2)

    P = 20 kgm/s

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )