How much work must be done on a particle with a mass of mm to accelerate it from rest to a speed of 0.084 cc ? (Express the answer in terms of mc2mc2.)
How much work must be done on a particle with a mass of mm to accelerate it from rest to a speed of 0.084 cc ? (Express the answer in terms of mc2mc2.)
Answer:
Work = 0.68 mc²
Explanation:
given data
speed = 0.084 cc
solution
as kinetic energy of mass particle is
KE = mc²([tex]\gamma[/tex] – 1 ) …………1
here [tex]\gamma[/tex] is lorentz constant
[tex]\gamma[/tex] = [tex]\frac{1}{\sqrt{1-(\frac{v}{c})^2 } }[/tex]
[tex]\gamma[/tex] = [tex]\frac{1}{\sqrt{1-(\frac{0.084c}{c})^2 } }[/tex]
[tex]\gamma[/tex] = 1.68
as here particle start from rent so initial KE is 0
and final KE = mc²(1.68 – 1 )
final KE = 0.68mc²
so here work done to increase speed of particle
W = final KE – initial KE
Work = 0.68 mc²