How much work is required to turn an electric dipole 180° in a uniform electric field of magnitude E = 46.0 N/C if the dipole moment has a m

Question

How much work is required to turn an electric dipole 180° in a uniform electric field of magnitude E = 46.0 N/C if the dipole moment has a magnitude of p = 3.02 × 10−25 C·m and the initial angle is 64°?

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Euphemia 5 years 2021-09-02T11:27:40+00:00 1 Answers 43 views 0

Answers ( )

  1. minhkhue
    0
    2021-09-02T11:29:09+00:00
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    Answer:

    W=1.22*10^{-23}J

    Explanation:

    Torque and energy of an electric dipole in an electric field we find:

    W=U(\alpha_{o}+\pi )-U(\alpha_{o} )=-pE(cos(\alpha_{o}+\pi )-cos(\alpha_{o} ))\\W=2pECos\alpha_{o}\\ W=2(3.02*10^{-25}C.m )(46.oN/C)Cos64\\W=1.22*10^{-23}J

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