How much work does it take to accelerate a 9.0 kg object from rest to 27 m/s? Group of answer choices 2200 J

Question

How much work does it take to accelerate a 9.0 kg object from rest to 27 m/s?

Group of answer choices

2200 J

6600 J

120 J

3300 J

0.33 J

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Thu Cúc 3 years 2021-09-04T16:03:15+00:00 1 Answers 5 views 0

Answers ( )

  1. Amity
    0
    2021-09-04T16:05:07+00:00
    Reply

    initial kinetic energy = 0J (v=0 (rest))

    Final kinetic energy = 1/2mv ²
    Ek=1/2(9)(27 ²)
    Ek=4.5(729)
    Ek=3280.5

    ∆Energy=3280.5J
    (As it starts from 0)

    Work= ∆energy
    So work =3280.5J

    Answer=3300J (forth option)

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