How much work did the movers do (horizontally) pushing a 46.0-kgkg crate 10.5 mm across a rough floor without acceleration, if the effective

Question

How much work did the movers do (horizontally) pushing a 46.0-kgkg crate 10.5 mm across a rough floor without acceleration, if the effective coefficient of friction was 0.50

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Maris 5 years 2021-08-05T05:36:15+00:00 1 Answers 47 views 0

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  1. Dulcie
    0
    2021-08-05T05:37:46+00:00
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    Answer:

    7.1 J

    Explanation:

    From the question,

    Work done by the mover  = work done in pushing the crate + work done against friction

    W = W’+Wf…………….. Equation 1

    W = mgd+mgμd………… Equation 2

    W = mgd(1+μ)……………. Equation 3

    Where m = mass of the crate, g = acceleration due to gravity, d = distance, μ = coefficient of  friction.

    Given: m = 46 kg, d = 10.5 mm = 0.0105 m, μ = 0.5

    constant: g = 9.8 m/s²

    Substitute these values into equation 3

    W = 46×9.8×0.0105(1+0.5)

    W = 7.1 J

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