How much conventional current must you run in a solenoid with radius = 0.05 m and length = 0.39 m to produce a magnetic field inside the sol

Question

How much conventional current must you run in a solenoid with radius = 0.05 m and length = 0.39 m to produce a magnetic field inside the solenoid of 2 × 10−5 T, the approximate field of the Earth? The solenoid has 200 turns.

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Neala 5 years 2021-08-29T05:33:32+00:00 1 Answers 31 views 0

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  1. Nick
    0
    2021-08-29T05:35:10+00:00
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    Answer:

    Explanation:

    radius of the solenoid, r = 0.05 m

    length of the solenoid, l = 0.39 m

    Magnetic field of the solenoid, B = 2 x 10^-5 T

    Number of turns, N = 200

    The magnetic field of the solenoid is given by

    B=\mu _{0}ni

    where, i be the current and n be the number of turns per unit length

    n = N / l = 200 / 0.39 = 512.8

    2\times 10^{-5}=4 \times 3.14\times 10^{-7}\times 512.8\times i

    i = 0.031 A

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