How much charge is needed to repel another charge of 9.9 x 10^-6 N when they are 200m apart? Please help meee I really can’t understand Coul

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How much charge is needed to repel another charge of 9.9 x 10^-6 N when they are 200m apart? Please help meee I really can’t understand Coulomb’s Law : (

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Ngọc Hoa 5 years 2021-08-31T18:57:06+00:00 1 Answers 15 views 0

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  1. thanhha
    0
    2021-08-31T18:58:11+00:00
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    Answer:

    The charge needed will be q=6.6\: \mu C

    Step-by-step explanation:

    The equation of the electric force is given by:

    F=k\frac{qQ}{r^{2}}

    We have the force F = 9.9 10^{-6}\: N  and the distance r = 200. k is the Coulomb constant. Q and q are the charges.

    We assume we have the same charge of the particles,  so we have:

    q^{2}=\frac{Fr^{2}}{k}

    q^{2}=\frac{9.9*10^{-6}200^{2}}{9*10^{9}}

    q=6.6*10^{-6}\: C

    Therefore, the charge needed will be q=6.6\: \mu C

    I hope it helps you!

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