how much amount of heat energy is required to convert 5 kg of ice at – 5° c into 100°c steam?​

Question

how much amount of heat energy is required to convert 5 kg of ice at – 5° c into 100°c steam?​

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Thu Thủy 5 years 2021-07-14T05:06:40+00:00 1 Answers 48 views 0

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    2021-07-14T05:08:25+00:00

    Assuming no heat lost to the surrounding,

    -5⁰C ice → 0⁰C ice

    Specific heat capacity of ice = 2.0 x 10³ J/kg/⁰C

    Q = mc∆θ

    Q = 5(2.0 x 10³) x (0-(-5))

    Q = 50000J

    0⁰C ice → 0⁰C water

    Specific latent heat of fusion of ice = 3.34 x 10⁵J/kg

    Q = mLf

    Q = 5(3.34 x 10⁵)

    Q = 1670000J

    0⁰C water → 100⁰C water

    Specific heat capacity of water = 4.2 x 10³ J/kg/⁰C

    Q = mc∆θ

    Q = 5(4.2 x 10³) x (100-0)

    Q = 2100000J

    100⁰C water → 100⁰C steam

    Specific latent heat of vaporization of water = 2.26 x 10⁶ J/kg

    Q = mLv

    Q = 5(2.26 x 10⁶)

    Q = 11300000J

    Total amount of heat required

    = 50000 + 1670000 + 2100000 + 11300000

    = 15120000J

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