How many total oxygen atoms are in the compound Molybdenum (V) Dichromate?

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How many total oxygen atoms are in the compound Molybdenum (V) Dichromate?

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RI SƠ 5 years 2021-07-31T06:08:32+00:00 1 Answers 23 views 0

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  1. Giakhanh
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    2021-07-31T06:09:34+00:00
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    Answer:

    1.2646\times10^{25}\ atoms

    Explanation:

    -The chemical formula for Molybdenum (V) Dichromate is Mo(Cr_2O_7)_3

    -There are 21 moles of oxygen per one mole of Molybdenum (V) Dichromate

    -We apply Avogadro’s constant to find the number of atoms of oxygen:

    Avogadro's \ Constant=6.022\times 10^{23} \ mol_1\\\\No\ of \ Atoms=Moles\times Avogadro's \ Constant\\\\=21\times 6.022\times 10^{23} \\\\=1.2646\times10^{25}\ atoms

    Hence, there are 1.2646\times10^{25} \ atoms

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