How many moles of NaCl are present in .05 L of 2.3 M NaCl solution?

Question

How many moles of NaCl are present in .05 L of 2.3 M NaCl solution?

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Ladonna 5 years 2021-09-03T07:49:03+00:00 2 Answers 23 views 0

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  1. Delwyn
    0
    2021-09-03T07:50:28+00:00
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    N = 1.15 mol so choose dat one 🙂 have a good day <3

  2. Adela
    0
    2021-09-03T07:50:36+00:00
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    Answer:

    n = 1.15 mol

    Explanation:

    C = n/ V

    n= C×V

    n= 2.3× 0.5

    n = 1.15 mol

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