How many milliliters of 5.0 M NaOH are needed to exactly neutralize 40. milliliters of 2.0 M HCl?

Question

How many milliliters of 5.0 M NaOH are needed to exactly neutralize 40. milliliters of 2.0 M HCl?

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Farah 5 years 2021-07-24T05:39:27+00:00 1 Answers 19 views 0

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  1. Acacia
    0
    2021-07-24T05:41:22+00:00
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    Answer:

    16mL

    Explanation:

    Using the following formula;

    CaVa = CbVb

    Where;

    Where

    Ca = concentration/molarity of acid (M)

    Va = volume of acid (mL)

    Cb = concentration/molarity of base (M)

    Vb = volume of base (mL)

    According to the information provided in this question;

    Ca (HCl) = 2M

    Cb (NaOH) = 5M

    Va (HCl) = 40mL

    Vb (NaOH) = ?

    Using CaVa = CbVb

    Vb = CaVa/Cb

    Vb = 2 × 40/5

    Vb = 80/5

    Vb = 16mL

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )