how many grams of silver medal could be recovered from a reaction of 50 g silver nitrate and copper metal

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how many grams of silver medal could be recovered from a reaction of 50 g silver nitrate and copper metal

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Ngọc Hoa 5 months 2021-08-19T19:33:00+00:00 1 Answers 5 views 0

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    2021-08-19T19:34:08+00:00

    Answer:

    Answer is: mass of copper is 127 grams.

    Balanced chemical reaction: Cu(s) + 2AgNO₃(aq) → Cu(NO₃)₂(aq) + 2Ag(s).

    m(Ag) = 432 g.

    n(Ag) = m(Ag) ÷ M(Ag).

    n(Ag) = 432 g ÷ 108 g/mol.

    n(Ag) = 4 mol.

    From chemical reaction: n(Ag) : n(Cu) = 2 : 1.

    n(Cu) = 4 mol ÷ 2 = 2 mol.

    m(Cu) = n(Cu) · M(Cu).

    m(Cu) = 2 mol · 63.5 g/mol.

    m(Cu) = 127 g

    Explanation:

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